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The values of k for which the system of equationsx+ky-3z=0 ,   3x+ky-2z=0  ,  2x+3y-4z=0 has a non-trivial solution is (are)

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a
2110
b
3110
c
-5
d
4

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detailed solution

Correct option is A

From (1) and (2), 2x+z=0⇒2x=-zFrom (3), we get 3y =5z∴x=-12z,y=53zSubstituting this in (1) we get -12z+5k3z-3z=0.⇒5k3-72z=0Now , z≠0⇒k=2110


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