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The values of $a$ for which the matrix $A = (\begin{array}{ccc} a & a^{2} - 1 & - 3 \\ a + 1 & 2 & a^{2} + 4 \\ - 3 & 4 a & - 1 \end{array})$ is symmetric are

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Correct option is D

A′=A aa+1−3a2−124a−3a2+4−1=aa2−1−3a+12a2+4−34a−1⇒a+1=a2−1 and 4a=a2+4⇒a+1=4a−4−1 ⇒ 6−3a ⇒ a=2.

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The values of a for which the matrix A=aa2−1−3a+12a2+4−34a−1 is symmetric are

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The values of $a$ for which the matrix $A = (\begin{array}{ccc} a & a^{2} - 1 & - 3 \\ a + 1 & 2 & a^{2} + 4 \\ - 3 & 4 a & - 1 \end{array})$ is symmetric are