The values of a for which one root of the equation x2−(a+1) x+a2+a−8 =0 exceeds 2 and the other is lesser than 2, are given by
a>3
9<a<10
−2<a<3
None of these
he given equation is x2−(a+1) x+a2+a−8 =0 …. ( 1 )
If the roots of the given equation are
real and distinct D>o⇒3a2+2a-33<0 ⇒a∈(-113,3)………(1)
and f(2) less than 0
⇒4-a+12+a2+a-8<0
so a∈(-2,3)……. ……..(2)
from 1&2 we get a∈(-2,3)