The values of x where the function f(x)=tanxlog(x−2)x2−4x+3 is discontinuous are given by
−∞,2
−∞,2∪3
(−∞,2)∪{3,nπ+π/2:n≥1}
None of these
f(x)=tanxlog(x−2)x2−4x+3, being product and quotient of functions tanx
log(x−2) and x2−4x+3 must be continuous in its domain of definition.
tanx is discontinuous in {(2n+1)π/2:n∈Z}
log(x−2) discontinuous for x≤2
and x2−4x+3=0 for x=1 and 3.
Hence f(x) is discontinuous in [−∞,2]∪{3,nπ+π/2:n∈Z}
[−∞,2]∪{3,nπ+π/2:n≥1}
Hence (3) is the correct answer.