Questions
a
−∞,2
b
−∞,2∪3
c
(−∞,2)∪{3,nπ+π/2:n≥1}
d
None of these
detailed solution
Correct option is C
f(x)=tanxlog(x−2)x2−4x+3, being product and quotient of functions tanxlog(x−2) and x2−4x+3 must be continuous in its domain of definition. tanx is discontinuous in {(2n+1)π/2:n∈Z}log(x−2) discontinuous for x≤2 and x2−4x+3=0 for x=1 and 3. Hence f(x) is discontinuous in [−∞,2]∪{3,nπ+π/2:n∈Z}[−∞,2]∪{3,nπ+π/2:n≥1}Hence (3) is the correct answer.Talk to our academic expert!
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