Values of x and y satisfying the equation sin7y=|x3−x2−9x+9|+|x3−x2−4x+4|+sec22y+cos4y  are

sin7y=|x3−x2−9x+9|+|x3−x2−4x+4| +sec22y+cos4y For x=1 sin7y=sec22y+cos4y ⇒sin7ycos22y=1+cos4ycos22y Since, LHS≤1. and RHS≥1 Which is possible only when ∴sin7ycos22y=1 ⇒sin7y=1 andcos22y=1;y=π2 General value of y is 2nπ+π2 Hence, x=1  and y=2nπ+π2,n∈I