The variance of first n natural numbers, is
n+12
n2+112
n2−16
n2−112
Here xi=i;i=1,2,…,n
∴ σ2 =1n∑i=1n xi2−1n∑i=1n xi2⇒ σ2 =1n12+22+…+n2−n+122⇒ σ2 =n(n+1)(2n+1)6n−n+122⇒ σ2 =(n+1)(2n+1)6−(n+1)24=n2−112