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Questions  

The variance of the first n natural numbers is 

a
n2−112
b
n2−16
c
n2+16
d
n2+112

detailed solution

Correct option is A

Variance =(SD)2=1nΣx2−Σxn2,∵x¯=Σxn                  =n(n+1)(2n+1)6n−n(n+1)2n2=n2−112

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