The variance of the numbers 2, 3,11 and x is494.find the value x .
6,143
6,145
6,163
None of these
From given data, we make the following table
But we know that, variance =Σx2n−Σxn2
⇒ 134+x24−16+x42=494⇒ 134+x24−256+x2+32x16=494⇒ 3x2−32x+28016=494⇒ 280+3x2−32x=494×16⇒ 280+3x2−32x=196⇒ 3x2−32x+84=0⇒ (x−6)(3x−14)=0⇒ x=6,x=143
Therefore, the values of x are 6 and 143.