The vector equation of the line passing through (1,2,3) and perpendicular to the plane r¯.(i¯+2j¯−5k¯)+9=0

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r¯=(i¯+2j¯+3k¯)+t(i¯+2j¯−5k¯)

r¯=(i¯−2j¯+3k¯)+t(i¯+2j¯−5k¯)

r¯=(i¯+2j¯+3k¯)+t(i¯−2j¯+5k¯)

r¯=(i¯+2j¯+3k¯)+t(i¯+2j¯+5k¯)

answer is A.

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Detailed Solution

Vector perpendicular to the plane is vector parallel to the required line r¯=a¯+tb¯a→=(1,2,3)b→=(-1,-2,5)

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