Q.

The vector equation of the line passing through the point (1,2,-4) and perpendicular to the two lines x−83=y+19−16=z−107 and x−153=y−298=z−5−5

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a

r¯=(i¯+2j¯+4k¯)+λ(2i¯+3j¯+6k¯)

b

r¯=(i¯+2j¯−4k¯)+λ(2i¯+3j¯+6k¯)

c

r¯=(i¯−2j¯+4k¯)+λ(i¯+3j¯+6k¯)

d

r¯=(i¯+2j¯−4k¯)+λ(2i¯−3j¯+6k¯)

answer is B.

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Detailed Solution

Dr's of a line perpendicular to a¯ and b¯ is a¯×b¯=i¯j¯k¯3−16738−5=24i¯+36j¯+72k¯=2i¯+3j¯+6k¯Equation of line passing through (1,2,-4) and parallel to a¯×b¯r¯=(i¯+2j¯−4k¯)+λ(2i¯+3j¯+6k¯)
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The vector equation of the line passing through the point (1,2,-4) and perpendicular to the two lines x−83=y+19−16=z−107 and x−153=y−298=z−5−5