Questions
Vector equation of the line
a
r= 3
b
r=i+2j+3k+λ(13i−13j+k)
c
r=13i−13j+k+λ(i+2j+3k)
d
r=−2i+j−2k+λ(6i+3j+2k) where λ is a parameter.
detailed solution
Correct option is C
The line can be written as x−1/31=y+1/32=z−13 which passes through the point whose position vector is (1/3)i−(1/3)j+k and is parallel to the vector i+2j+3k and hence its equation is r=13i−13j+k+λ(i+2j+3k).Talk to our academic expert!
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