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Q.

The vector equation of the plane passing through the intersection of the planes r→.i^+j^+k^=1 and r→.i^−2j^=−2 and the point 1,0,2 is

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a

r→.i^+7j^+3k^=73

b

r→.3i^+7j^+3k^=7

c

r→.i^−7j^+3k^=73

d

r→.i^+7j^+3k^=7

answer is D.

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Detailed Solution

The equation of the plane passing through the line of intersection of two planes   x+y+z=1and x−2y+2=0  is x+y+z−1+λx−2y+2=0          It is passing through the point 1,0,2          Hence, 2+λ3=0=λ=−23          Therefore, the equation of the required plane is x+7y+3z−7=0 , this can be written as    r→⋅i+7j+3k=7
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The vector equation of the plane passing through the intersection of the planes r→.i^+j^+k^=1 and r→.i^−2j^=−2 and the point 1,0,2 is