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The vector equation of the plane passing through the line of intersection of two planes x−2y+3z−1=0,2x+y+z−2=0 and passing through the point (1,2,3) is

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a

r¯.i¯+3j¯−2k¯−1=0

b

r¯.i¯−3j¯−2k¯−1=0

c

r¯.i¯+3j¯−2k¯+1=0

d

r¯.i¯+3j¯−2k¯−3=0

answer is A.

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Detailed Solution

x−2y+3z−1+λ(2x+y+z−2)=0 Substituting in above equation (1,2,3)1−4+9−1+λ(2+2+3−2)=05+5λ=0⇒λ=−1 Required equation x−2y+3z−1−2x−y−z+2=0⇒x+3y−2z−1=0

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