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Questions  

 The vector equation of the plane passing through the line of intersection of two planes 

x2y+3z1=0,2x+y+z2=0 and passing through the point (1,2,3) is 

a
r¯.i¯+3j¯−2k¯−1=0
b
r¯.i¯−3j¯−2k¯−1=0
c
r¯.i¯+3j¯−2k¯+1=0
d
r¯.i¯+3j¯−2k¯−3=0

detailed solution

Correct option is A

x−2y+3z−1+λ(2x+y+z−2)=0 Substituting in above equation (1,2,3)1−4+9−1+λ(2+2+3−2)=05+5λ=0⇒λ=−1 Required equation x−2y+3z−1−2x−y−z+2=0⇒x+3y−2z−1=0

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