The vector equation of the plane passing through the origin and the line of intersection of the planes r→.a→=λ and r→⋅b→=μ is
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a
r→⋅(λa→−μb→)=0
b
r→⋅(λb→−μa→)=0
c
r→⋅(λa→+μb→)=0
d
r→⋅(λb→+μa→)=0
answer is B.
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Detailed Solution
The equation of a plane through the line of intersection of the planes r→⋅a→=λ and r→⋅b→=μ is (r→⋅a→−λ)+k(r→⋅b→−μ)=0or r→⋅(a→+kb→)=λ+kμ--------iPutting the value of k in (i), we get the equation of the required plane as r→⋅(μa→−λb→)=0 or r→⋅(λb→−μa→)=0