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Questions  

 The vector equation of the plane passing through the origin  and the line of intersection of the planes r.a=λ and rb=μ is 

a
r→⋅(λa→−μb→)=0
b
r→⋅(λb→−μa→)=0
c
r→⋅(λa→+μb→)=0
d
r→⋅(λb→+μa→)=0

detailed solution

Correct option is B

The equation of a plane through the line of intersection of the  planes r→⋅a→=λ and r→⋅b→=μ is (r→⋅a→−λ)+k(r→⋅b→−μ)=0or   r→⋅(a→+kb→)=λ+kμ--------iPutting the value of k in (i), we get the equation of the required plane as r→⋅(μa→−λb→)=0 or r→⋅(λb→−μa→)=0

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