The vector r→ satisfying the equations r→×a→=b→×a→ and r→×b→=a→×b→ is ----- , where a→=i^+j^;b→=2i^−k^
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a
i^−j^+k^
b
3i^−j^+k^
c
3i^+j^−k^
d
i^−j^-k^
answer is C.
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Detailed Solution
r→×a→=b→×a→ or (r→−b→)×a→=0r→×b→=a→×b→ or (r→−a→)×b→=0 If r→=xi^+yj^+zk^, then i^j^k^x−2yz+1110=0 and i^j^k^x−1y−1z20−1=0⇒ z+1=0,x−y=2 and y−1=0,x−1+2z=0⇒ x=3,y=1,z=−1