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Q.

The  vector r→ satisfying the equations  r→×a→=b→×a→ and r→×b→=a→×b→ is -----    , where a→=i^+j^;b→=2i^−k^

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a

i^−j^+k^

b

3i^−j^+k^

c

3i^+j^−k^

d

i^−j^-k^

answer is C.

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Detailed Solution

r→×a→=b→×a→ or (r→−b→)×a→=0r→×b→=a→×b→ or (r→−a→)×b→=0 If r→=xi^+yj^+zk^, then i^j^k^x−2yz+1110=0 and i^j^k^x−1y−1z20−1=0⇒ z+1=0,x−y=2 and  y−1=0,x−1+2z=0⇒ x=3,y=1,z=−1
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