Vectors a→=−4i^+3k^;b→=14i^+2j^−5k^ are laid off from one point. Vector d→ which is being laid off from the same point dividing the angle between vector, a→ and b→ in equal halves and having the magnitude 6, is
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a
i^+j^+2k^
b
i^−j^+2k^
c
i^+j^−2k^
d
2i^−j^−2k^
answer is A.
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Detailed Solution
a^=−4i+3k^5;b^=14i^+2j^−5k^15 A vector V→ bisecting the angle between a→ and b→isV→=a^+b^=−12i^+9k^+14i^+2j^−5k^15=2i^+2j^+4k^15 Required vector d→=6V^=i^+j^+2k^