A vertical pole stands at a point A on the boundary of a circular park of radius ‘a’ and subtends an angle β at another point B on the boundary. If the chord AB subtends an angle α at the center of the park, the height of the pole is
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a
2asinα2tanβ
b
2acosα2tanβ
c
2asinα2cotβ
d
2acosα2cotβ
answer is A.
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Detailed Solution
Suppose that h be the height of the pole from triangle APB,tanβ=hAB⇒h=ABtanβ from triangle ABC,sinα2=AB2a⇒AB=2asinα2∴h=2asinα2tanβ