Questions
The vertices of a OBC are O (0, 0), B(–3, –1) and C(–1, –3). The equation of a line parallel to BC and intersecting sides OB and OC whose distance from the origin is , is
a
x+y+12=0
b
x+y-12=0
c
x+y-12=0
d
x+y+12=0
detailed solution
Correct option is A
The equation of line BC is x + y + 4 = 0 ∴Equation of a line parallel to BC is x + y + k = 0This is at a distance 12 from the origin.∴ k2=12∴ k=±12Since BC and the required line are on the same side of the origin∴ k=12Hence, the required line is x+y+12=0Talk to our academic expert!
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If the equation of the locus point equidistant from the points and is then the value of c is
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