The vertices of a parallelogram ABCD are A3,1,B13,6,C13,21 and D3,16. If a line passing through the origin divides the parallelogram into two congruent parts, then the slope of the line is
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a
11/12
b
11/8
c
25/8
d
13/8
answer is B.
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Detailed Solution
Slope of line through origin is, m=21−x13=x+13or 63−3x=13x+13or 16x=50or x=258Hence, m=258+1×13=3324=118