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$Vertices of a parallelogram taken in order are A (2, - 1, 4),$ $B (1, 0, - 1), C (1, 2, 3) and D . Distance of the point$ $P (8, 2, - 12) from the plane of the parallelogram is -$

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Correct option is B

n→=7i^+2j^-k^ is normal to plane , this is AB X AC (Assuming n=ai^+bj^+ck^ and using AP¯=6i^+3j^-16k^∴ Distance d=AP¯·n→|n→|=42+6+1649+4+1=6454=6436=64618=3269

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Vertices of a parallelogram taken in order are A(2,-1,4) , B(1,0,-1),C(1,2,3) and D. Distance of the point P(8,2,-12) from the plane of the parallelogram is -

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$Vertices of a parallelogram taken in order are A (2, - 1, 4),$ $B (1, 0, - 1), C (1, 2, 3) and D . Distance of the point$ $P (8, 2, - 12) from the plane of the parallelogram is -$