The vertices of a triangle are $$A(1$$,$$0$$,$$2)$$,$$B(2$$,$$3$$,$$0)$$,$$C(0$$,$$0$$,$$4)$$ then the symmetric form of the line passing through centroid of the triangle and one vertex B is

Question

The vertices of a triangle are $$A(1$$,$$0$$,$$2)$$,$$B(2$$,$$3$$,$$0)$$,$$C(0$$,$$0$$,$$4)$$ then the symmetric form of the line passing through centroid of the triangle and one vertex B is

Infinity Learn · Accepted Answer

The centroid of the triangle formed by the points $$A(1$$,$$0$$,$$2)$$,$$B(2$$,$$3$$,$$0)$$,$$C(0$$,$$0$$,$$4)$$  is $$G=1+23$$,$$33$$,$$2+43=(1$$,$$1$$,$$2)The$$ equation of the line joining two points $$A(x1$$,$$y1$$,$$z1)$$ and $$B(x2$$,$$y2$$,$$z2)$$ is x−$$x1x2$$−$$x1=y$$−$$y1y2$$−$$y1=z$$−$$z1z2$$−$$y1The$$ equation of the line joining two points (1$$,$$1$$,$$2) and $$2$$,$$3$$,$$0$$ is x−$$12$$−$$1=y$$−$$13$$−$$1=z$$−$$20$$−$$2This$$ can be rewrite as x−$$11=y$$−$$12=z$$−$$2$$−$$2$$

The vertices of a triangle are $A (1, 0, 2), B (2, 3, 0), C (0, 0, 4)$ then the symmetric form of the line passing through centroid of the triangle and one vertex $B$ is

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The vertices of a triangle are A(1,0,2),B(2,3,0),C(0,0,4) then the symmetric form of the line passing through centroid of the triangle and one vertex B is

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The vertices of a triangle are $A (1, 0, 2), B (2, 3, 0), C (0, 0, 4)$ then the symmetric form of the line passing through centroid of the triangle and one vertex $B$ is