The vertices of a triangle are A(−1,−7),B(5,1) and C(1,4). The equation of the bisector of ∠ABC is:
7x+y−36=0
x−7y+2=0
both (a) and (b)
neither (a) nor (b)
Bisector BD of ∠ABC divides AC in 2:1
∴ D=(1/3,1/3) .
∴ Equation of BD is y−1=2/314/3(x−5)
⇒ x−7y+2=0 .