Questions
The vertices of a triangle are at O (0, 0), A (a, 0) and B (0, b). The distance between its circumcentre and orthocentre is
a
a2+b2
b
12a2+b2
c
a2+b22
d
14a2+b2
detailed solution
Correct option is B
Clearly, ∆OAB is a right triangle right angled at O. So, its orthocentre is at O (0, 0) and circumcentre is the mid- point o its hypotenues i.e. a2,b2∴Required distance=a2−02+b2−02=12a2+b2Talk to our academic expert!
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If an triangle circumcentre and orthocentre then the coordinates of the midpoint of the side opposite to A are
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