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The vertices of the triangle $A B C$ are $A (1, 2),$ $B (0, 0)$ and $C (2, 3),$ then the greatest angle of the triangle is

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75°

105°

120°

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detailed solution

Correct option is D

Sides of the triangle area=BC=4+9=13,b=2,c=5The greatest angle A is given bycos⁡A=b2+c2−a22bc=2+5−132×2×5=−310.

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The vertices of the triangle ABC are A(1, 2),B (0, 0) and C(2, 3), then the greatest angle of the triangle is

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The vertices of the triangle $A B C$ are $A (1, 2),$ $B (0, 0)$ and $C (2, 3),$ then the greatest angle of the triangle is