The vertices of the triangle ABC are A(1, 2),B (0, 0) and C(2, 3), then the greatest angle of the triangle is
75°
105°
120°
None of these
Sides of the triangle are
a=BC=4+9=13,b=2,c=5
The greatest angle A is given by
cosA=b2+c2−a22bc=2+5−132×2×5=−310.