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Questions  

the vlaue of  21C110C1+ 21C210C2+ 21C310C3+ 21C410C4++ 21C1010C10is

a
221−211
b
221−210
c
220−29
d
220−210

detailed solution

Correct option is D

21C1−10C1+ 21C2−10C2+ 21C3−10C3+…+ 21C10−10C10 =21C1+21C2+…+21C10− 10C1+10C2+…+10C10 =12 21C1+21C2+…+21C20−210−1=12 21C1+21C2+…+21C21−1−210−1=12221−2−210−1=220−1−210+1=220−210

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