The volume of a tetrahedron formed by the coterminus edges a→,b→ and c→ is 3 hen the volume of the parallelepiped formed by the coterminus edges a→+b→,b→+c→ and c→+a→ is

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answer is C.

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Detailed Solution

3=16[a→b→c→] or [a→b→c→]=18Volume of the required parallelepiped=[a→+b→b→+c→c→+a→]=2[a→b→c→]=36

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