The volume of the tetrahedron formed by the coterminus edges a→,b→,c→ is 3 .  Then the volume of the parallelepiped formed by the coterminus edges a→+b→,b→+c→,c→+a→ is

16  [a→  b→  c→]  =  3   ⇒  [a→  b→  c→]   =   18 Volume of the required parallelepiped =a→   +  b→       b→ + c→      c→ + a→  =110011101 a→  b→  c→ =    2a→  b→  c→   =   36