The volume of the tetrahedron formed by the coterminus edges a→,b→,c→ is $$3$$ . Then the volume of the parallelepiped formed by the coterminus edges a→$$+b$$→,b→$$+c$$→,c→$$+a$$→ is

Question

The volume of the tetrahedron formed by the coterminus edges a→,b→,c→ is $$3$$ .  Then the volume of the parallelepiped formed by the coterminus edges a→$$+b$$→,b→$$+c$$→,c→$$+a$$→ is

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$$16$$  [a→  b→  c→]  $$=$$  $$3$$   ⇒  [a→  b→  c→]   $$=$$   $$18$$ Volume of the required parallelepiped $$=a$$→   $$+$$  b→       b→ $$+$$ c→      c→ $$+$$ a→  $$=110011101$$ a→  b→  c→ $$=$$    $$2a$$→  b→  c→   $$=$$   $$36$$

$The volume of the tetrahedron formed by the coterminus edges \vec{a}, \vec{b}, \vec{c} is 3 .$ $Then the volume of the parallelepiped formed by the coterminus edges$ $\vec{a} + \vec{b}, \vec{b} + \vec{c}, \vec{c} + \vec{a} is$

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The volume of the tetrahedron formed by the coterminus edges a→,b→,c→ is 3 . Then the volume of the parallelepiped formed by the coterminus edges a→+b→,b→+c→,c→+a→ is

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$The volume of the tetrahedron formed by the coterminus edges \vec{a}, \vec{b}, \vec{c} is 3 .$ $Then the volume of the parallelepiped formed by the coterminus edges$ $\vec{a} + \vec{b}, \vec{b} + \vec{c}, \vec{c} + \vec{a} is$