The volume of the tetrahedron formed by the coterminus edges a→,b→,c→ is 3 . Then the volume of the parallelepiped formed by the coterminus edges a→+b→,b→+c→,c→+a→ is

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answer is C.

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Detailed Solution

16 [a→ b→ c→] = 3 ⇒ [a→ b→ c→] = 18 Volume of the required parallelepiped =a→ + b→ b→ + c→ c→ + a→ =110011101 a→ b→ c→ = 2a→ b→ c→ = 36

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