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Q.

The weighted mean of first n natural numbers whose weights are equal is given by

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a

n+12

b

2n+12

c

2n+13

d

(2n+1)(n+1)6

answer is A.

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Detailed Solution

Let w be equal weight. Then Required mean =1⋅w+2⋅w+3⋅w+…+n⋅ww+w+w+…+w=n(n+1)2wnw=n+12
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The weighted mean of first n natural numbers whose weights are equal is given by