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The weighted mean of first n natural numbers whose weights are equal to the number of selections out of n natural numbers of corresponding numbers, is

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a
n⋅2n−12n−1
b
3n(n+1)2(2n+1)
c
(n+1)(2n+1)6
d
n(n+1)2

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detailed solution

Correct option is A

The required meanx¯=1⋅nC1+2⋅nC2+3⋅nC3+…+n⋅nCn nC1+nC2+…+nCn=∑r=0n r⋅nCr∑r=1n nCr=∑r=1n r⋅nrn−1Cr−1∑r=1n nCr=n⋅2n−12n−1


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