What is the equation of the plane which passes through the e-axis and is perpendicular to the line x−acos⁡θ=y+2sin⁡θ=z−30?

The plane is perpendicular to the line x−acos⁡θ=y+2sin⁡θ=z−30Hence , the direction ratios of the normal of the plane are cos⁡θ,sin⁡θ and 0.Now, the required plane passes through the e-axis. Hence, the point (0, 0, 0) lies on the plane.Thus, we get equation of the plane as cos⁡θ(x−0)+sin⁡θ(y−0)+0(z−0)=0cos⁡θx+sin⁡θy=0x+ytan⁡θ=0