Questions
What is the equation of the plane which passes through the e-axis and is perpendicular to the line
a
x+ytanθ=0
b
y+xtanθ=0
c
xcosθ−ysinθ=0
d
xsinθ−ycosθ=0
detailed solution
Correct option is A
The plane is perpendicular to the line x−acosθ=y+2sinθ=z−30Hence , the direction ratios of the normal of the plane are cosθ,sinθ and 0.Now, the required plane passes through the e-axis. Hence, the point (0, 0, 0) lies on the plane.Thus, we get equation of the plane as cosθ(x−0)+sinθ(y−0)+0(z−0)=0cosθx+sinθy=0x+ytanθ=0Talk to our academic expert!
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The equation of a plane which passes through the point of intersection of lines and and at greatest distance from point (0,0,0) is
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