For what value of x the angle between vectors a→=xi^−3j^−k^ and b→=2xi^+xj^−k^ is acute
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
1
b
2
c
0
d
0.5
answer is B.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Let a→=xi^−3j^−k^ and b→=2xi^+xj^−k^ be the adjacent sides of the parallelogram Now angle between a→ and b→ is acute, i.e., |a→+b→|>|a→−b→|⇒|3xi^+(x−3)j^−2k^|2>|−xi^−(x+3)j^|2or 9x2+(x−3)2+4>x2+(x+3)2or 8x2−12x+4>0or 2x2−3x+1>0or (2x−1)(x−1)>0⇒ x<1/2 or x>1Hence, the least positive integral value is 2.