For what value of x, the matrix 3−x2224−x1−2−4−1−x is singular

Since, the given matrix is singular⇒3−x2224−x1−2−4−1−x=0Applying R2→R2+R3⇒3−x222−x−x−2−4−1−x=0  ⇒ x 3−x22011241+x=0⇒  x{(3−x)(1+x−4)−0+2(2−2)}=0⇒     x{(3−x)(x−3)}=0⇒  x=0,  3