First slide

Theorems of probability

Question

When a card is drawn from a pack, then the probability of getting a number card is

Easy

A

$\frac{1}{13}$
B

$\frac{1}{4}$
C

$\frac{9}{13}$
D

$\frac{1}{2}$

Solution

$A, 2, 3, 4, 5, 6, 7, 8, 9, 10, J, Q, K$
$n (A) = 36_{c_{1}}$

$n (S) = 52_{c_{1}}$

$P (A) = \frac{36}{52} = \frac{9}{13}$

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