First slide

Theorems of probability

Question

When a die is rolled thrice. The probability of getting triplet is

Easy

A

$\frac{1}{6}$
B

$\frac{1}{36}$
C

$\frac{1}{26}$
D

$\frac{1}{16}$

Solution

$A = {(1, 1, 1,), (2, 2, 2), (3, 3, 3), (4, 4, 4), (5, 5, 5), (6, 6, 6)}$
$n (A) = 6,$ $n (S) = 6. 6. 6 = 6^{3} = 216$

$P (A) = \frac{1}{36}$

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