When x=52, numerically greatest term in the expansion of (3+2x)15 is
6th
8th
10th
12th
Use the formula (n+1)|x|1+|x| in (1+x)n 3+2x15=3151+2x315 (n+1)|x|1+|x|=15+1|2x3|1+|2x3|=16531+53=808=10 10th, 11th terms are numerically greatest terms.