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a
If A and B are square matrices of order 3 such that|A|=−1,|B|=3 ,then the determinant of 3 AB is equal to 27
b
If A is an invertible matrix, thendet(A−1) is equal todet(A)
c
If A and B are matrices of the same order ,then(A+B)2=A2+2AB+B2 is possible if:AB=I
d
None of these
answer is D.
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Detailed Solution
(a) we have |AB|=|A||B| Also for a square matrix of order3, |KA|=K3|A| because each element of the matrix A is multiplied by k and hence in this case we will have K3 commonSince A is invertible, therefore exists and ∴|3AB|=33|A||B|=27(−1)(3)=−81 (b) Since A is invertible, thereforeA−1 for exists andAA−1=1⇒det(AA−1)=det(I) ⇒det(A)det(A−1)=1⇒det(A−1)=1det(A) (c) (A+B)2=(A+B)(A+B) =A2+AB+BA+B2=A2+2AB+B2 if AB=BA