Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

Which of the following is correct to the line  5x+y+3z=0 and 3x−y+z+1=0

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

Symmetrical form of the equation of line isx2=y−18−1=z+581

b

Symmetrical form of the equations of line is x+181=y−581=z−2

c

Equation of the plane through (2,-1,4) and perpendicular to the given line is 2x−y+z−7=0

d

Equation of line through (2,-1,4) and perpendicular to the given line isx+y−2z+5=0

answer is B.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

The given planes are  5x+y+3z=0 and 3x−y+z+1=0Suppose that the direction ratios of line of intersection of the above two planes is ⟨a,b,c⟩Hence, 3a−b+c=0,5a+b+3c=0⇒a1=b1=c−2To get a point on the line, substitute z=0  in the plane equations and the solve for the other variables hence a point on the  line of intersection of planes is P-18,58,0Therefore, the equation of the required line is x+181=y−581=z−2
Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring