Questions
Which of the following is correct to the line and
a
Symmetrical form of the equation of line isx2=y−18−1=z+581
b
Symmetrical form of the equations of line is x+181=y−581=z−2
c
Equation of the plane through (2,-1,4) and perpendicular to the given line is 2x−y+z−7=0
d
Equation of line through (2,-1,4) and perpendicular to the given line isx+y−2z+5=0
detailed solution
Correct option is B
The given planes are 5x+y+3z=0 and 3x−y+z+1=0Suppose that the direction ratios of line of intersection of the above two planes is ⟨a,b,c⟩Hence, 3a−b+c=0,5a+b+3c=0⇒a1=b1=c−2To get a point on the line, substitute z=0 in the plane equations and the solve for the other variables hence a point on the line of intersection of planes is P-18,58,0Therefore, the equation of the required line is x+181=y−581=z−2Talk to our academic expert!
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The line intersects the curve if c=
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