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Q.

Which of the following is correct. (Where[.] is G.I.F)

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a

limx→0[ex][ex]=1

b

limx→π2   cos−1[cot  x]=π2

c

limx→0xx=1

d

limx→0[x][x]=1

answer is .

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Detailed Solution

A) x→0+⇒x>0⇒ex>1        [ex]=1  R.H.L=1​​    x<0−⇒x<0   ex<1           [ex]=0 L.H.L= indeterminate B) x→π+2⇒cot  x<  cot π2⇒[cot  x]=−1 ∴R.H.L=π      L.H.L=π2C) limx→0xx=1D) Limit does not exist
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