Which of the following functions are identical?
f(x)=lnx2 and g(x)=2lnx
f(x)=logxe and g(x)=1logex
f(x)=sincos−1x and g(x)=cossin−1x
None of these
(1) For f(x)=logx2, x2>0 or x∈R−{0}
For g(x)=2logx, x>0
Hence, f(x) and g(x) are not identical.
(2) f(x)=logxe=1logex=g(x)
Hence, the functions are identical.
(3) f(x)=sincos−1x=sinπ2−sin−1x=cossin−1x=g(x)