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a
y =1 - log10x
b
y=e−2x
c
y=sin−1(2x+1)
d
y=tan(4x+1)
answer is C.
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Detailed Solution
The range log10x is (−∞,∞) so y=1−log10xis unbounded y=e−2x is unbounded from below as x→−∞ y→∞. The range of sin−1x is −π2,π2 so y=sin−1(2x+1) isa bounded function. The range of tan x is R so y = tan (4x + 1) is unbounded