which of the following lines lie on the plane x + 2y - z + 4 = 0

For line x-11=y-1=z-5-1 , point (1, 0, 5) lies on the plane.Also, the vector along the line i^-j^-k^ is perpendicular to the normal i^+2j^-k^ to the plane.For liner→=2i^-j^+4k^+λ(3i^+j^+5k^), point (2, -1,4) lies on the plane and vector 3i^+j^+5k^is perpendicular to the normal i^+2j^-k^Line x - y + z = 2x + y - z = 0 passes through the origin, which is not on the given plane.