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Which of the following lines lies on the plane x+2y-z+4=0

a
x−11=y−1=z−5−1
b
x−y+z=0=2x+y−z
c
x−21=y2=z−53
d
x−21=y-2=z−5-3

detailed solution

Correct option is A

The condition that the line x−x1l=y−y1l=z−z1n lies on the plane ax+by+cz+d=0 is  al+bm+cn=0 and ax1+by1+cz1+d=0Verify each option and then finalize the answer. The given plane is x+2y-z+4=0For the option(1), 11+2-1-1-1=1-2+1=0and 11+20-15+4=1-5+4=0Therefore, the linex−11=y−1=z−5−1  lies on the plane x+2y-z+4=0, , the option (1) is the answer.

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