Which of the following lines lies on the plane x+2y-z+4=0

The condition that the line x−x1l=y−y1l=z−z1n lies on the plane ax+by+cz+d=0 is  al+bm+cn=0 and ax1+by1+cz1+d=0Verify each option and then finalize the answer. The given plane is x+2y-z+4=0For the option(1), 11+2-1-1-1=1-2+1=0and 11+20-15+4=1-5+4=0Therefore, the linex−11=y−1=z−5−1  lies on the plane x+2y-z+4=0, , the option (1) is the answer.