First slide

Introduction to linear inequalities

Question

$Which of the following is not the solution of \frac{16^{1 / x}}{2^{x + 3}} > 1 ?$

Moderate

A

$(- \infty, - 4)$
B

$(0, 1)$
C

$(0, \infty)$
D

None of these

Solution

$\begin{array}{l} 2^{\frac{4}{x} - x - 3} > 2^{0} \\ \Rightarrow \frac{4}{x} - x - 3 > 0 \\ \Rightarrow \frac{4 - x^{2} - 3 x}{x} > 0 \\ \Rightarrow \frac{x^{2} + 3 x - 4}{x} < 0 \\ \Rightarrow \frac{(x + 4) (x - 1)}{x} < 0 \\ \Rightarrow x \in (- \infty, - 4) \cup (0, 1) \end{array}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App