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a
(−5,−2)
b
(−1,∞)
c
(−5,−1)
d
None of these
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Correct option is C
We have |x+3|+xx+2>1 Clearly, LHS of this inequation is meaningful for x≠−2 . Now |x+3|+xx+2−1>0⇒ |x+3|−2x+2>0 If |x+3|−2=0⇒x+3=±2⇒x=−5,−1 Hence, the sign scheme of the expression |x+3|−2x+2 is as follows: From the above sign scheme x∈(−5,−2)∪(−1,∞) .Similar Questions
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