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Q.

For which of the following ordered pairs (μ,δ), the system of linear equations x+2y+3z=1, 3x+4y+5z=μ and 4x+4y+4z=δis inconsistent?

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a

4,6

b

1,0

c

3,4

d

4,3

answer is D.

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Detailed Solution

Note D=345123444R3→R3-2R1+3R2=345123000=0 Now let P3=4x+4y+4z-δ=0 . If the system has solutions it will have infinite  solution, so P3=αP1+βP2 Hence 3α+β=4 & 4α+2β=4⇒α=2&β=-2 So for infinite solution 2μ-2=δ⇒ for 2μ≠δ+2system inconsistent
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