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a
4,6
b
1,0
c
3,4
d
4,3
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Correct option is D
Note D=345123444R3→R3-2R1+3R2=345123000=0 Now let P3=4x+4y+4z-δ=0 . If the system has solutions it will have infinite solution, so P3=αP1+βP2 Hence 3α+β=4 & 4α+2β=4⇒α=2&β=-2 So for infinite solution 2μ-2=δ⇒ for 2μ≠δ+2system inconsistentSimilar Questions
If the system of equations , is consistent, then value of a is given by
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