Which of the following is the solution set of the equation 2cos−1x=cot−12x2−12x1−x2?

2cos−1x=cot−12x2−12x1−x2Putx=cosθ ; L.H.S. = 2θ where   0≤θ≤πand −1≤x≤1 ………  (1)R.H.S. = cot−1cos2θ2cosθ|sinθ|=cot−1(cot2θ)=2θ    if  0<2θ<π     ………….  (2) From (1) and (2), we get      0<θ<π/2                     ∴x∈(0,1)