Which of the following is the solution set of the equation 2cos−1x=cot−12x2−12x1−x2?
(0,1)
(−1,1)−{0}
(-1,0)
[-1,1]
2cos−1x=cot−12x2−12x1−x2
Putx=cosθ ; L.H.S. = 2θ where 0≤θ≤πand −1≤x≤1 ……… (1)
R.H.S. = cot−1cos2θ2cosθ|sinθ|=cot−1(cot2θ)=2θ if 0<2θ<π …………. (2)
From (1) and (2), we get 0<θ<π/2
∴x∈(0,1)