Which of the following is the solution set of the equation sin−1x=cos−1x+sin−1(3x−1)?
0,13
13,23
0,23
none of these
For the existence of the given equation, we must have
−1≤x≤1 and −1≤3x−1≤1⇒0≤x≤23
Now,
sin−1x=cos−1x+sin−1(3x−1)⇒ sin−1x−cos−1x=sin−1(3x−1)⇒ 2sin−1x−π2=sin−1(3x−1)⇒ sin2sin−1x−π2=sinsin−1(3x−1)⇒ −cos2sin−1x=3x−1⇒ −1−2sin2sin−1x=3x−1⇒ −1−2x2=3x−1⇒ 2x2−3x=0⇒x=0,32⇒x=0 [∵0≤x≤2/3]