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a
xsgnx=|x|
b
|x|sgnx=x
c
x(sgnx)(sgnx)=x
d
|x|(sgnx)3=|x|
answer is D.
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Detailed Solution
Checking the options (a) LHS =xsgnx=x×(+1)=x if x>0x×0=0 if x=0x×(−1)=−x if x<0 =|x|= RHS Therefore, statement is correct. b LHS =|x|sgnx=(+x)×(+1)=x if x>00×0=0 if x=0(−x)×(−1)=x if x<0Therefore, statement is correct. (c) LHS=(x(sgnx))×sgnx=|x|sgnx=x=RHSTherefore, statement is correct. (d) LHS =(|x|sgnx)(sgnx)2=x(sgnx)2=|x|×(sgnx)=x ≠RHSTherefore, statement is incorrect.