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a
xsgnx=|x|
b
|x|sgnx=x
c
x(sgnx)(sgnx)=x
d
|x|(sgnx)3=x
answer is D.
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Detailed Solution
|x|= {−x; x<00; x=0x; x>0 and sgn(x) ={−1; x<00; x=01; x>0 ∴ (A) xsgnx={−x, if x<00, if x=0x, if x>0⇒ xsgnx=|x| (B) |x|sgnx=(−x)(−1)=x, if x<0 (0)(0)=0, if x=0 (x)(1)=x, if x>0 ⇒|x|sgnx=x (C) x(sgnx)(sgnx)=x (D) |x|(sgnx)3=(−x)(−1)3=x if x<0 (0)(0)3=0, if x=0 (x)(1)3=x, if x>0 ∴ |x|(sgnx)3=x not |x| .