Which of the following is true?
~p∧(p⇔q)≡[~(p⇒q)∧~(q⇒p)]
p⇒q≡∼p⇒∼q
~(p⇒∼q)≡∼p∧q
~(~p⇒∼q)≡∼p∧q
~(p⇒q)≡~p∧~q~(~p⇒∼q)≡∼p∧~(~q)≡~p∧q Thus ~(~p⇒∼q)≡~p∧q
Hence, (d) is the correct answer.