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a
~p∧(p⇔q)≡[~(p⇒q)∧~(q⇒p)]
b
p⇒q≡∼p⇒∼q
c
~(p⇒∼q)≡∼p∧q
d
~(~p⇒∼q)≡∼p∧q
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Correct option is D
~(p⇒q)≡~p∧~q~(~p⇒∼q)≡∼p∧~(~q)≡~p∧q Thus ~(~p⇒∼q)≡~p∧qHence, (d) is the correct answer.Similar Questions
The false statement in the following is
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